Risk of Ruin

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New member
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Nov 25, 2009
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Hi All,

I need some advice regarding the appropriate amount of units to have in one's bankroll if only betting 1 unit per selected game. For example, if I intend to bet $100 on a selected game, how much should I have in my total bankroll to have a risk of ruin of 1%?

A formula from a poker book (The Mathematics of Poker) I have regarding the risk of ruin for outcomes that follow a normal distribution is as follows:

R(b) = exp{ (-2*mu*b) / sigma^2 }

Where R(b) is the formula for risk of ruin, mu is the winrate, b is the size of the bankroll, and sigma^2 is variance.

I'm having trouble working out what a way to work out an expected winrate (mu) and variance (sigma^2). I will only be placing bets for the sake of making money and not just action. Any help on this would be appreciated.
 

A Separate Reality
Joined
Jan 14, 2002
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This looks like the Kelly Criterion. Your win rate is your percentage of winning minus your percentage of losing. A 55% winning percentage minus a 45% losing percentage gives you a 10% win rate. You bet 10% of your bankroll fixed so the variance is minimal? Thats my best guess.

Good luck with the betting for the sake of making money not action... that is where the risk of ruin lives.
 

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